b^2+2b+1=16

Solution for b^2+2b+1=16 equation:

Simplifying
b2 + 2b + 1 = 16

Reorder the terms:
1 + 2b + b2 = 16

Solving
1 + 2b + b2 = 16

Solving for variable 'b'.

Reorder the terms:
1 + -16 + 2b + b2 = 16 + -16

Combine like terms: 1 + -16 = -15
-15 + 2b + b2 = 16 + -16

Combine like terms: 16 + -16 = 0
-15 + 2b + b2 = 0

Factor a trinomial.
(-5 + -1b)(3 + -1b) = 0

Subproblem 1
Set the factor '(-5 + -1b)' equal to zero and attempt to solve:

Simplifying
-5 + -1b = 0

Solving
-5 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + -1b = 0 + 5

Combine like terms: -5 + 5 = 0
0 + -1b = 0 + 5
-1b = 0 + 5

Combine like terms: 0 + 5 = 5
-1b = 5

Divide each side by '-1'.
b = -5

Simplifying
b = -5
Subproblem 2
Set the factor '(3 + -1b)' equal to zero and attempt to solve:

Simplifying
3 + -1b = 0

Solving
3 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1b = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1b = 0 + -3
-1b = 0 + -3

Combine like terms: 0 + -3 = -3
-1b = -3

Divide each side by '-1'.
b = 3

Simplifying
b = 3
Solution
b = {-5, 3}